Log in T T Reza Digonto 5 years agoPosted 5 years ago. Direct link to T T Reza Digonto's post “here we can see that hook...” here we can see that hooke's law has limitations..is there any alternate law which overcomes hooke's law? like bohrs atomic model overcomed rutherfords model. • (6 votes) photon_dynamics 5 days agoPosted 5 days ago. Direct link to photon_dynamics's post “Yes, Hooke's Law, which s...” Yes, Hooke's Law, which states that the force needed to extend or compress a spring by a certain distance is proportional to that distance, has limitations, especially when dealing with materials that do not exhibit linear elasticity. One alternative law that overcomes the limitations of Hooke's Law is the non-linear stress-strain relationship described by the theory of plasticity. Plasticity theory accounts for the permanent deformation of materials under applied loads beyond the elastic limit, where Hooke's Law no longer applies. This theory is essential in understanding the behavior of materials under large deformations and high stresses. (1 vote) mmazmatullah 6 years agoPosted 6 years ago. Direct link to mmazmatullah's post “Among stress and strain w...” Among stress and strain which quantity is independent and dependent?? ganeshrvenkatraman 5 years agoPosted 5 years ago. Direct link to ganeshrvenkatraman's post “stress is always dependen...” stress is always dependent on how the system (or body) is constrained (resisted from accelerating). strain is however independent of this.. It is possible to have strains without stress too.. (3 votes) laihuaqing 5 years agoPosted 5 years ago. Direct link to laihuaqing's post “What happens if we graphe...” What happens if we graphed the steel bar's stress for the neck as well? Would it instead shoot straight up? • (3 votes) INFINITE IQ 4 years agoPosted 4 years ago. Direct link to INFINITE IQ's post “probably. Until the fract...” probably. Until the fracture point i think it would still keep increasing (3 votes) Kaushik 5 years agoPosted 5 years ago. Direct link to Kaushik's post “Hey! Why is the yield poi...” Hey! Why is the yield point beyond proportionality limit? • (1 vote) ganeshrvenkatraman 5 years agoPosted 5 years ago. Direct link to ganeshrvenkatraman's post “steel still retains its o...” steel still retains its original configuration when stressed beyond the proportionality limit. this happens till yielding sets in (yield point). however the stress beyond proportionality limit varies non linearly vs strain. This gap is usually very small. (3 votes) Hope T 3 years agoPosted 3 years ago. Direct link to Hope T's post “So point A is called prop...” So point A is called proportional limit point, is the point above any applied stress doesn't obey linear stress-strain behavior (Hooke's Law). And the elastic limit or yield point is the point where a combination of elastic and plastic behavior is still there (although it's not in the plastic region) so according to ASKLAND BOOK at that point the departure of the plastic behavior is noticeable unlike Proportional limit where the plastic behavior is on a microscopic level. So know my question is: why he said if the stress that is applied on the specimen is between both proportional limit point and yield point will return fully as if it's elastic ?! I think that is wrong. Since there is also plastic behavior (small) beside the elastic the specimen will retain but some deformation will be there isn't it ? • (2 votes) Dish*ta 2 years agoPosted 2 years ago. Direct link to Dish*ta's post “No real body is perfectly...” No real body is perfectly elastic. (1 vote) Andrew Livingstone 5 years agoPosted 5 years ago. Direct link to Andrew Livingstone's post “why if the strain increas...” why if the strain increasing and the stress is decreasing? • (2 votes) Dish*ta 2 years agoPosted 2 years ago. Direct link to Dish*ta's post “rewatch the video, he exp...” rewatch the video, he explains it. (1 vote) Dish*ta 2 years agoPosted 2 years ago. Direct link to Dish*ta's post “Let's say I have 2 materi...” Let's say I have 2 materials, P.S: my teacher said B is stronger cuz the area under the graph is larger. How does that make sense? • (1 vote) Ethan.M 2 years agoPosted 2 years ago. Direct link to Ethan.M's post “How do I calculate the ma...” How do I calculate the material thickness needed for a given metal, in • (1 vote)Want to join the conversation?
Even within the proportional limit, there will be microfractures (minute).
So, there will be some degree of deformation if a body is strained.
It's just that within B, the material can return to its original dimensions without undergoing a noticeable plastic (permanent) deformation.
Think about a rubber band, it loses elasticity after being used frequently even if strained below the strain corresponding to the yield point.
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6:59
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ultimate tensile strength of A is greater than that of B,
but, the region of plastic deformation of A is lesser than that of B.
Isn't A stronger than B?
i.e., if A was diamond and B steel (as in the video), diamond is definitely stronger.
the cylindrical part of the internal combustion chamber?
